What would be the formula to show the age of a person as of today? I need the result in years

[Sandra_McCann]

DATETIME_DIFF([date1], [date2], ‘units’)

I saw this formula but how do I modify it to include my fields and a result in years for the units?

[Tim_Wilson]

Here’s my age formula: DATETIME_DIFF(TODAY(), Birthday, ‘years’)

I have a field named “Birthday” in my table that contains the birthdate.

[Tech_Tylercivic]

I use Tim’s method, understanding you get an “ERROR” if the birthday field is not filled in.

[Sophie_Zifcak]

What do I do If I need my output to be years and months?

[Matt_Bush]

To get the age of a person in months:
DATETIME_DIFF(TODAY(), Birthday, 'months')
-> 346

Modifying the above to always give you the remainder when dividing by years, using MOD:
MOD(DATETIME_DIFF(TODAY(), Birthday, 'months'), 12)
-> 10

Finally, concatenating that with the age in years and adding units:
DATETIME_DIFF(TODAY(), Birthday, 'years') & ' years, ' & MOD(DATETIME_DIFF(TODAY(), Birthday, 'months'), 12) & ' months'
-> 28 years, 10 months

[Greg_Maye]

For the formula to work for me, I needed to make: , Birthday, => ,{Birthday},

Thanks for the help.

[Nussi_Einhorn]

Trying to use your DATETIME_DIFF(TODAY(), Birthday, ‘years’)

Still getting that error!! Please help!

[Nussi_Einhorn]

Please send me the entire code formula! Thanks.

[Greg_Maye]

DATETIME_DIFF(TODAY(), {Birthday}, ‘years’)

And {Birthday} is a field in my table, of course.

Hope that works for you.

[Nussi_Einhorn]

Still giving the formula error!