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Re: Within a Repeating Group, update a multiple select field without overwriting

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jlw21
4 - Data Explorer
4 - Data Explorer

I've read the solutions for how to update a multiple select field without overwriting via automation. However, I have a bit of a wrinkle—this doesn't seem to be possible when using a Repeating Group.

The background:

I have a list of live performances in a table called Shows. I have a list of performers in a table called Artists. The two tables are linked via a Linked Record field so that Artists (one or more) can be added to specific shows.

Some Artists perform on shows year after year. I have a multiple select field in the Artists table for "Years Active."

The desired automation:

When an Artist is attached to a show, I'd like the "Years Active" field in the Artist's record to update to include "2024" in addition to any existing years already in the field.

The issue:

Normally, I would insert the current value of "Years Active" followed by a comma and then "2024." However, the only two fields I can insert are the record ID and name field. This seems to be a limitation of working within a Repeating Group. I'm hoping someone smarter than I can figure out a different way to approach this issue, or point out what I'm doing wrong. Thanks for reading!

1 Solution

Accepted Solutions
kuovonne
18 - Pluto
18 - Pluto

Within your repeating group, do a "Find Records" action to get the current record that you want to process. The easiest way to do this is have a formula field with RECORD_ID(), and then search based on that field. Finally, in your "Update Record" action, pull the existing multiple select value for the record from the "Find Records" result.

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3 Replies 3
kuovonne
18 - Pluto
18 - Pluto

Within your repeating group, do a "Find Records" action to get the current record that you want to process. The easiest way to do this is have a formula field with RECORD_ID(), and then search based on that field. Finally, in your "Update Record" action, pull the existing multiple select value for the record from the "Find Records" result.

jlw21
4 - Data Explorer
4 - Data Explorer

Brilliant, that worked like a charm. Thank you so much, @kuovonne !

wooti
6 - Interface Innovator
6 - Interface Innovator

Super helpful, thank you so much!