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Mar 09, 2021 08:59 AM
I am trying to create a formula to return the difference in time between two dates in terms of the number of months and number of days. For example, being age “8 months 3 days.”
This is the formula I came up with so far, but this direction doesn’t get me an accurate return since not every month has exactly 30 days in it:
(DATETIME_DIFF({DATE},‘2 Feb 2020’,‘M’)) & " mos " & ((DATETIME_DIFF({DATE},‘2 Feb 2020’, ‘d’))-(DATETIME_DIFF({DATE},‘2 Feb 2020’, ‘M’))*30) & " days "
Any ideas? Maybe I need to start over using different functions?
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Mar 21, 2021 06:30 PM
Got it! I’m posting my solution here, in case anyone else is interested. This formula will accurately return an age as “X months, X days.”
(DATETIME_DIFF({DATE}, ‘2 FEB 2020’, ‘months’) ) & ’ mos, ’ & (DATETIME_DIFF((DATEADD({DATE}, -(DATETIME_DIFF({DATE}, ‘2 FEB 2020’, ‘months’) ), ‘month’)), ‘2 Feb 2020’, ‘days’)) & ’ days’
Notes:
- {DATE} refers to a column containing the date of the event.
- Replace ‘2 FEB 2020’ with the birthday.

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Mar 21, 2021 06:30 PM
Got it! I’m posting my solution here, in case anyone else is interested. This formula will accurately return an age as “X months, X days.”
(DATETIME_DIFF({DATE}, ‘2 FEB 2020’, ‘months’) ) & ’ mos, ’ & (DATETIME_DIFF((DATEADD({DATE}, -(DATETIME_DIFF({DATE}, ‘2 FEB 2020’, ‘months’) ), ‘month’)), ‘2 Feb 2020’, ‘days’)) & ’ days’
Notes:
- {DATE} refers to a column containing the date of the event.
- Replace ‘2 FEB 2020’ with the birthday.
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