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Hello all,

Forgive me for what seems like a silly question, I’m new to this and can’t figure this out. I would like to launch a website when I click a button in the scripting block. Is this possible?


let purpose = await input.buttonsAsync(

'Are you Creating a Record?',

 

    {label: 'Create', value: 'creating'}

],

);

if (purpose === 'creating') {

//LAUNCH URL HERE

}

Scripting block itself cannot launch a webpage. Scripting block can display a link (in markdown format) to a web page, and when the user clicks the link, the web page will open. Note that the web page will open the browser window, no in the Scripting block window.

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